Suppose a,b,c are in A.P. and a2,b2 ,c2 are in G.P. If a<b<c and a+b+c =3/2then the value of a isa)b)c)d)Correct answer is option 'D'. Can you explain this answer? | EduRev
![If a2, b2, c2 are in A.P., prove that 1/b+c, 1/c+a, 1/a+b is also in AP. Also prove the converse is - Brainly.in If a2, b2, c2 are in A.P., prove that 1/b+c, 1/c+a, 1/a+b is also in AP. Also prove the converse is - Brainly.in](https://hi-static.z-dn.net/files/d4f/a88418ee58500fb9e8c0c2654c57a1a7.jpg)
If a2, b2, c2 are in A.P., prove that 1/b+c, 1/c+a, 1/a+b is also in AP. Also prove the converse is - Brainly.in
![SOLVED: Consider the proof. Given: In △ABC, BD ⊥ AC Prove: the formula for the law of cosines, a2 = b2 + c2 – 2bccos(A) Triangle A B C is shown. A SOLVED: Consider the proof. Given: In △ABC, BD ⊥ AC Prove: the formula for the law of cosines, a2 = b2 + c2 – 2bccos(A) Triangle A B C is shown. A](https://cdn.numerade.com/ask_previews/9a354ecb-a9d7-4a29-8e28-14a75f4a715f_large.jpg)